Question

Which of the following is the solution to the equation 8^(y - 2) = 2y

Answer 1

y = 1
y = 3
y = -3
y = -1

Answer 2

\[\Huge 8^{y - 2} = 2^y~~~~~,~~~~~\text{Use}~~8=2^2\]
\[\Huge 2^{2(y - 2)} = 2^y\]
Since the base are same, you can bring down the exponents
2(y-2)=y
Try to solve from here?

Answer 3

8(y-2)= 2y
8y-16=2y
6y=16
y =8/3 ??

Answer 4

i get an answer but its not one of the choices

Answer 5

Did you follow the steps?

Answer 6

I always come out with y=8/3
64/3 - 48/3 =16/3
16/3 = 16/3 it checks

Answer 7

or im confused haha

Answer 8

You need to change the 8 to 2,
\[\Huge 8^{y - 2} = 2^y~~~~~,~~~~~\text{Use}~~8=2^3\]
\[\Huge 2^{3(y - 2)} = 2^y\]
Then
3(y-2)=y

Answer 9

3y-6=y
2y=6
y=3

Answer 10

thank you