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would it be B?
if i change my picture to a chick do more people help me with my problems???
huh?
no lol
(x - y)^4 Use Pascal's Triangle. Row 4 is 1, 4, 6, 4, 1 1(x^4)(1) + 4(x^3)(y) + 6(x^2)(y^2) + 4(x)(y^3) + 1(1)(y^4) x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4
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look 5 people viewing the problems..lol
it sounds like your upset? its not my fault im a girl..
\[(a+b)^r=\sum_{r=0}^{n} \left(\begin{matrix}n \\ r\end{matrix}\right) a^{n-r} b^r\]
soo A?
Oh. I forgot the negatives. Hold on.
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1(x^4)(1) + 4(x^3)(y) + 6(x^2)(y^2) + 4(x)(y^3) + 1(1)(y^4) x^4 - 4x^3y + 6x^2y^2 - 4xy^3 + y^4
C..awesome!
help me now >.>
your pathetic.
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