what is this equation 1/2*m*v^2 = 3/2*k*T?

Question

anonymous · Answer

Kinetic Energy =???

anonymous · Answer

Kinetic Energy

anonymous · Answer

what is the purpose of the equation? what does the equation describe?  Ive never seen 3/2*k*t

stormfire1 · Answer

It's used to calculate the kinetic energy of an ideal gas where k is Boltzmann's constant and T is the temperature of the gas in Kelvin. For a better explanation of the equation go to http://www.ux1.eiu.edu/~cfadd/1150/14Thermo/kinetic.html

stormfire1 · Answer

Absolutely nothing would happen...literally :)

stormfire1 · Answer

Note the intended pun.

anonymous · Answer

seriously?? what would happen based on the equation?

stormfire1 · Answer

$$\frac{1}{2}mv^2=\frac{3}{2}kT$$so if T was 0:$$\frac{1}{2}mv^2=\frac{3}{2}k*0$$which to me implies what we already know...velocity must also be 0.

stormfire1 · Answer

If you're asking what would happen if you went below absolute 0 then I'd say the question is flawed.  Absolute 0 is the idea that all particles essentially have 0 velocity...

anonymous · Answer

@shakir

anonymous · Answer

@ajprincess

anonymous · Answer

@Brent0423  it is kinetic energy equation and k is called boltzman constant,

anonymous · Answer

KE=3/2KT

anonymous · Answer

@shakir what do u think?

anonymous · Answer

@stormfire1  is correct @Brent0423  .....

ajprincess · Answer

I too agree with @stomfire1's answer. @Brent0423

anonymous · Answer

@shakir