Question

If the circle (x + 5)2 + (y - 4)2 = 35 is translated 5 units down and 4 units right, then the sum of the new y-intercepts is?

Answer 1

If the circle (x + 5)^2 + (y - 4)^2 = 35 is translated 5 units down and 4 units right, then the sum of the new y-intercepts is

Answer 2

(x +5)^2 + (y-4)^2= 35
new position, it becomes.
(x+5-4)^2 +(y-4+5)^2=35
(x+1)^2 + (y+1)^2 =35
now for y intersept put x=0
1+ (y+1)^2 = 35
(Y+1)^2=34
\[(y+1)= \pm \sqrt{34}\]
\[y=\pm \sqrt{34} -1\]

sum of intersepts.
\[- \sqrt{34} +1 + \sqrt{34} +1=2\]

Answer 3

sorry -2

Answer 4

thank you

Answer 5

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