Question

a block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. if a force F is applied at one end of the rope, what is the force which the rope exerts on the block?

Answer 1

F..
action reaction pair.. (rope is taut, assumed.. jo ho gaa hi..)

Answer 2

thanks!!

Answer 3

I think it will be a little less than F (depending upon mass of rope).
This is because the tension in the rope is not constant as the rope is having mass and is accelerated under the force F and the force that the block applies on it (Let it be F1)

Acceleration of system is: F/(M+m)

So net force on rope = m*(F/(M+m)) {m*a}

i.e. F-F1=m*(F/M+m)
F1 =M*(F/M+m)
And this is the required answer