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Mathematics 19 Online
OpenStudy (anonymous):

How many combinations are possible if a committee of 3 is chosen from a group of 25 people?

Parth (parthkohli):

obviously 25c3. Because we are choosing 3 from 25.

OpenStudy (anonymous):

There is a total of 2,300 combinations.

OpenStudy (anonymous):

*are

Parth (parthkohli):

\(\Large \color{Black}{\Rightarrow 25c3 = {25! \over (25 - 3)! \times 3!} }\)

Parth (parthkohli):

Looks like someone just answered it.

OpenStudy (anonymous):

Remember - this is a combination problem, so you want to do 25 C 3. When you do that, you are finding out the total number of combinations that you could possibly have. Also, remember that combinations can repeat.

OpenStudy (anonymous):

so 2300 is the answer?

Parth (parthkohli):

Yes.

OpenStudy (anonymous):

Yes, 2300 is the answer.

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

You're very welcome! =)

OpenStudy (anonymous):

Sorry - @ParthKohli - I'm not sure what you mean?

Parth (parthkohli):

Maybe the moderators will tell you about it

OpenStudy (anonymous):

Did I do something wrong?

OpenStudy (anonymous):

Did I do something wrong? What do the moderators need to tell me about - I'm confused.

OpenStudy (anonymous):

@LyraElizabethAdams It's probably that you should show the steps or help them get the answer rather than just blurt it out.

OpenStudy (anonymous):

OH, I see! Okay - sorry! I thought that since I put the explanation beneath the answer, that was pretty much the same. I'll remember that next time. Thanks! :)

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