Let z_1=2+3i and z_2=1-i. Perform the indicated operations and write the solutions in the form a+bi.
|z_2|= ?

Question

Let z_1=2+3i and z_2=1-i. Perform the indicated operations and write the solutions in the form a+bi.
|z_2|= ?

anonymous · Answer

a. -1-i
b. 1+i
c. -1+i
d. sqrt2

anonymous · Answer

Underscore refers to base

amorfide · Answer

what do you mean by base?

anonymous · Answer

z_1= z and then a little one right beside the z

amorfide · Answer

okay so 
|dw:1338495487118:dw|
this means the modulus of z_2
modulus is Pythagoras
so you do 1² + (-i)²=1 + i²=1-1
1-1=0
root 0=0
modulus=0

i assume this is what you mean? unless the base means something different lol sorry

anonymous · Answer

Yes this is what I mean. Thanks! But I don't think it matches with any of the options :\

anonymous · Answer

modulus is sqrt((1^2)+(-1)^2)

anonymous · Answer

simplify that...

anonymous · Answer

Simplified to sqrt2! Thanks!

amorfide · Answer

my bad i squared i not the imaginary part of i sorry

anonymous · Answer

I wish I could give more than one medal. Thanks amorfide for the help and explanation!

anonymous · Answer

we'll split it... :)