Question

Show that a line through (0, 0) and (c, d) is perpendicular to a line through (0, 0) and (-d, c).

Slope of first line =

Slope of second line =

Answer 1

well if a slope is y/x then a perpendicular one is -x/y

Answer 2

soit would b 0?

Answer 3

so
d/c firls line

-c/d second line

Answer 4

wrong answers.. those are not it

Answer 5

tried those already

Answer 6

you say sow that a line through (0, 0) and (c, d) is perpendicular to a line through (0, 0) and (-d, c).


i am showing that :P

Answer 7

:/ i already tried sthose... :c

Answer 8

well you arer right :)

Answer 9

Show that a line through (0, 0) and (c, d) is perpendicular to a line through (0, 0) and (-d, c).

Slope of first line =

Slope of second line =

---------------

well line through (0, 0) and (c, d) has slope (d-0)/(c-0)=d/c

a line through (0, 0) and (-d, c). has slope (c-0)/(-d-0)=-(c/d)


therfore d/c was inverted and multiplied by -1 to make it perpendicular

Answer 10

all you need to do to show that two lines are perpendicular is multiply their slopes...
if it equals -1, you're done...
if it does not, then they are not perpendicular.

Answer 11

wait so what do i put :/

Answer 12

the rules is to just take a slope invert it and multiply by negative one

y/x -x/y

1/2 -2/1

3/5 -5/3

d/c - c/d

because well line through (0, 0) and (c, d) has slope (d-0)/(c-0)=d/c

a line through (0, 0) and (-d, c). has slope (c-0)/(-d-0)=-(c/d)