Solve: T(3) = 3/√3^2+9
the square root covers the 3 squared plus nine.
Thank you!

Question

Solve: T(3) = 3/√3^2+9
the square root covers the 3 squared plus nine. 
Thank you!

anonymous · Answer

wait, is there meant to be an t, x or some kind of pronumeral in there?

anonymous · Answer

it was T(L)=3/√L^2+9, T(3)=    Originally

anonymous · Answer

$$T(L)=3\div \sqrt{L^2+9}$$

anonymous · Answer

yes kk. 
T(3) = $$3 \div \sqrt{L^2 + 9}$$
       = 3 / sqrt 3^2 + 9
       = 3 / sqrt 18
      =  3/ 3sqrt 2.
      = 1/sqrt 2

anonymous · Answer

sorry, I wish that the equation symbol and typing all the symbols would have been more smooth and easy to do, but in fact it's not.

anonymous · Answer

yeah i know. my teacher said the answer is $$\sqrt{2}\div2$$

mertsj · Answer

$$T(3)=\frac{3}{\sqrt{3^2+9}}=\frac{3}{\sqrt{18}}=\frac{3}{3\sqrt{2}}=\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2}$$

anonymous · Answer

How did you go from 1/√2 to √2/2?

mertsj · Answer

$$\frac{1}{\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{2}$$