@amistre64 can you tell me how to use your method in exact DE for this?? $$(2x+y)dx + (x^2 - x)dy = 0$$ it seems i end up in a dead end :/

Question

anonymous · Answer

linear DE!
i got integration factor=(x-1)/x

experimentx · Answer

$$ e^{\int{\frac1{x(x-1)}}dx}$$

anonymous · Answer

the ans is $$y(x-1/x)+logx=c$$
@experimentX is it correct?

anonymous · Answer

(x-1)/x not x-1/x

experimentx · Answer

lol not sure ... 
$$ \frac{1}{x(x-1)} = \frac{-1}{x} + \frac{1}{x-1}$$

experimentx · Answer

Looks like you are right!!

anonymous · Answer

hmn!

amistre64 · Answer

does Fxy = Fyx?

amistre64 · Answer

2x NOTequal 2x-1; therefore its not "exact"

amistre64 · Answer

opps, well, same unequal outcome but i didnt do the left part right did i?

amistre64 · Answer

2x + y wrt y = 1

x^2-x wrt x = 2x -1

1 notequal 2x-1 so it aint exact

lgbasallote · Answer

so it's not exact?? weird :/