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Mathematics 15 Online
OpenStudy (anonymous):

Can someone thoroughly explain Synthetic Division to me? i mean, -Very- thorough. Polynomial Synthetic division.

OpenStudy (amistre64):

its simple enough, the setup is usually whats a bit odd at first

OpenStudy (anonymous):

But i dun get it ;_;

OpenStudy (amistre64):

provide an example that we can work thru

OpenStudy (anonymous):

\[x^2+8x+15 \div x+3\]

OpenStudy (anonymous):

a simple one...

OpenStudy (amistre64):

good, now synthD is all about format; so use something that suits you the best

OpenStudy (amistre64):

first we look at the top part, the numerator, and make sure all the positions are filled in in this case we start with an x^2; we should have positions for x^1 and x^0, if not use a 0 as a placeholder

OpenStudy (amistre64):

this one has all the positions filled in so we are good in that regards

OpenStudy (amistre64):

does this make sense?

OpenStudy (anonymous):

hmm, yes it does i suppose, yes

OpenStudy (anonymous):

thank you ^W^

OpenStudy (amistre64):

fill this in for me then so i can see how well your grasping this first step: x^4 + x^2 + 2

OpenStudy (anonymous):

alright, so the coefficients are... 0 0 2 right?

OpenStudy (amistre64):

we would need to fill in two extra zeros, yes; now the format part. I find it easiest to leave in the variables;

OpenStudy (amistre64):

x^4 + 0 + x^2 + 0 + 2

OpenStudy (amistre64):

i see no sens ein stripping away the variables and making extra work; we dont use them, but they dont get in the way either

OpenStudy (anonymous):

it would be something like l 0 0 0 0 2 --------- i think it was?

OpenStudy (amistre64):

something like that. but lets go back to yours step 2, find what I call a "root"; what makes the denominator a zero?

OpenStudy (anonymous):

errr...um, it's opposite value maybe?

OpenStudy (anonymous):

like, 1 and -1?

OpenStudy (amistre64):

x+3 = 0 when x = ?

OpenStudy (anonymous):

well, x would equal -3

OpenStudy (amistre64):

then lets make the "root" = -3 forget about trying to remember x+c and negate the c stuff

OpenStudy (amistre64):

now for the set up; becuase the rest is just add , multiply, add, multiply etc ...

OpenStudy (amistre64):

poly in this row 0 <-----add this row ---------------- r ) <-----multiply this row

OpenStudy (amistre64):

i leave the variables in; but we just work the coeffs x^2 +8x +15 0 ------------- -3 )

OpenStudy (amistre64):

if we wanted we could reduce the powers as we go and get the final result; but thats neither here not there

OpenStudy (anonymous):

alright then

OpenStudy (anonymous):

i think i may have it... maybe

OpenStudy (amistre64):

lets work this thru then, and maybe one more example

OpenStudy (amistre64):

first we add, what is 1 + 0?

OpenStudy (anonymous):

1

OpenStudy (amistre64):

x^2 +8x +15 0 ------------- -3 ) 1 what is -3 * 1?

OpenStudy (anonymous):

-3

OpenStudy (amistre64):

x^2 +8x +15 0 -3 ------------- -3 ) 1 what is 8 - 3?

OpenStudy (anonymous):

5

OpenStudy (amistre64):

x^2 +8x +15 0 -3 ------------- -3 ) 1 5 what is -3 * 5?

OpenStudy (anonymous):

-15

OpenStudy (amistre64):

x^2 +8x +15 0 -3 -15 ------------- -3 ) 1 5 0 and 15-15 = 0 and we are done with it

OpenStudy (anonymous):

Ohhhhh...Ok, this makes sense now, Thank you so much!

OpenStudy (amistre64):

if we had reduced the powers as we went: x^2 +8x +15 0 -3 -15 ------------- -3 ) 1x +5 R0 x+5 , remainder of zero

OpenStudy (amistre64):

dont confuse format for operation; format is what makes things simpler for you to work with. therefore format it to what you are camfortable with :)

OpenStudy (amistre64):

lets do another one just to clinch it up

OpenStudy (amistre64):

or not, its up to you :)

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