Who here knows how to graph on a computer the rolls of 2 dice and how many rolls go by until a 7? And the dice rolls are determined randomly by the computer. Does anyone know how to do this? I graphed it by hand which is time consuming to get an accurate graph and I don't accurately remember how the graph went but it was something like this: 1st roll: 9%, 2nd roll 8% third roll 7percent 4th roll 6% 5th roll 5% 6th roll 6% 7th roll 7% and from the 8th roll to the 40the it proceeds to be an exponential curve such that the 30th to 50th roll approach 99.9% probability of a 7.
For one roll, probability(P) of rolling a seven is 1/6, and the P of rolling a non-seven is 5/6. For success on the second roll, you must roll one non-seven, followed by one seven: (5/6)*(1/6). For success on any subsequent single roll “n”: (5/6)^(n-1) * (1/6). To compute how many rolls to hit a seven, you sum the P of all single rolls, from roll 1 to roll n. This gives you your limit function, approaching 1. e.g. Chance of a seven on exactly the 12th roll: 0.02243 – Chance of a seven in twelve rolls: 0.88784 You can build that table out easily in a spreadsheet, then chart it to see the function.
Impossible, it would be interesting to see the graph. I think you can start counting on the roll following a 7, another 7 could be the first.
Do I get a Nobel prize?
I had to draw it out to figure it out, here's a pic of what mine looks like:
Impossible.
Break the bank at the casino before everyone else does.
How can past dice rolls affect the present? Quantum insanity.
No. Nothing ever affects your current throw except loaded dice. Every throw, by itself, is a 1 in 6 chance. (six combinations that total 7, out of a set of 36 possible combinations.) The chance that this set of rolls succeeds becomes more probable as you make each throw. I didn't say what I meant to, in my first post. Disregard that muck I said about "chance of the current roll." You do still need to sum the series (5/6)^(n-1)*(1/6) for n = 1 to #rolls, in order to compute your percentage, as far as I can tell. Chance of throwing a single roll, hitting seven = 1 in 6. (16.6%) (not sure where 9% came from?...) Chance of throwing two rolls, and odds of a seven are 1 in 3.27. (30.6%) Three rolls, and odds of a seven are 1 in 2.37. etc... Running my chart out to 50 rolls does give you about a 1 in 1.0001 chance (99.989%) BUT, remember, that's how many rolls it takes to hit a *single* seven, not a run of sevens. You're taking multiple tries, for a single result. -And rolling a seven is good odds, to begin with. Four tries at a 1-in-6 shot, and you're right at even money. You hit 99.126% probability at 26 tries. A run of sevens would be totally different. Rolling twice, and hitting two sevens, would be a 1 in 36 chance (2.78%) and it just gets worse from there. It's not amazing that people don't break the bank. Chances are 2 in 3 that you'll shoot a point, and then seven's a loser. Ouch. Sorry, First post, I didn't know about the Medal system on this website. Thought you were joking about a Nobel Prize.
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