find the slope of the line that passes through each pair of points. (7/3,4/3),(-1/3,2/3)
do you have an initial answer?
i mean if you have tried solving it
yes
before you helped me I was trying to solve by graphing each line & it was taking forever. I turned the fractions into decimals and got m=1/2 at first but that sounded incorrect. Now I dont know how to solve
yup it's not 1/2
first step is 2/3 - 4/3 remember in subtracting fractions you just subtract the numeratirs and copy the denominator so it becomes \[\frac{2-4}[3}\] got it?
i mean \[\frac{2-4}{3}\]
oh.... I did not know that. I'm going back to high school after 10 yrs. So I do not remember that. ..... Ok so if it's the same denominator we use for both?
yup
so \[\LARGE slope = \frac{\frac{-1 - 7}{3}}{\frac{2-4}{3}}\]
so then we have \[\left(\begin{matrix}-2/3 \\ -8/3\end{matrix}\right)\]
oops yeah
sorry i got mine topsy turvy
\[\LARGE slope = \frac{\frac{-8}{3}}{\frac{-2}{3}}\] now...the 3 cancels out
so you're left with \[\frac{-8}{-2}\]
because \[\LARGE \frac{\frac{a}{c}}{\frac{b}{c}} = \frac{a}{b}\]
got it?
yes I got it. Does it turn into a positive since both numerators are negative?
yes
ok. Great thank you. Now that I have that part and gave u a medal. I'm going to post another question since I do not get the next section.
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