solve2x^2 =32
first divide both sides by 2 - what do you get?
32 divided by 2 is 16
thats the right-hand-side, what about the left-hand-side of the equation?
2 divided by 2 = 1 right
yes - so what is the resulting equation after dividing both sides by 2?
2^2 =16 right ?
not quite, you started with:\[2x^2=32\]where has the \(x^2\) gone?
oh yes umm we didit solve forx s it would be x^2 = 16 ?
perfect! no take the square roots of both sides and what do you get?
*now
x = 256 because 16x16 = 256
not quite - you have squared 16 instead of taking its square root. what number, when multiplied by itself, will give you 16?
4
thats it - well done. so, to summarise the steps, you did:\[2x^2=32\]then divide both sides by 2 to get:\[x^2=16\]then take square roots of both sides to get:\[x=4\]
have been taught that the square root can be negative as well?
*have you been...
yes
ok, in that case the answer should really be:\[x=\pm4\]
hope that makes sense?
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