Question

Try for fun. If [x/{l(mb+nc-la)}]=[y/{m(nc+la-mb)}]=[z/{n(la+mb-nc)}]; prove that
[l/{x(by+cz-ax)}]=[m/{y(cz+ax-by)}]=[n/{z(ax+by-cz)}]

Answer 1

what did i just read

Answer 2

lolnope I'm good

Answer 3

[l/{x(by+cz-ax)}]=[m/{y(cz+ax-by)}]=[n/{z(ax+by-cz)}]

It's done
any more problem?