Question

Fool's problem of the day,

A panel of eight umpires (A, B, C, D, E, F, G and H) is selected for officiating all the Cricket matches played in 2002. The countries which they represent (belong to) are P, Q, R, S, T, U and V, not necessarily in the same order.

(i) In the panel, B and D only belong to the same country i.e., T, while the others represent different countries.

(ii) A belongs to one of the subcontinent countries i.e., Q or U, while G belongs to the other.

(iii) The match between R and V is officiated by E and H.

(iv) H is does not belong to country P.

Note:- The umpires of the same country as the 2 countries that are playing the match cannot officiate in the match.

\(Q_1\): If a match is played between countries Q and V, then how many different combinations of umpires for that match are possible?

\(Q_2\): If in the above question, it is given that E and H are good friends, and always officiate together in a match, then how many different combinations of umpires are possible for the match between Q and V?

Attribution: I faced this question in a selectional test conducted by my coaching institute IMS ( http://www.imsindia.com/ )

Answer 1

Dont know if I'm way off here, but I think its Q1;(9) and Q2;(0)

Answer 2

No.

Answer 3

Damn, will try again

Answer 4

Is it just me, or is the majority of this information extraneous?

Answer 5

Yea nbouscal that is what i feel too. Thats why i don't think i got the right answer

My answer:
Q1. 49
Q2. 25

Answer 6

I was getting Q1. 15 and Q2. 7

Answer 7

May we know the real answer. Thanks!

Answer 8

The only suitable umpires I could be sure of are B, D, E and H
giving the answers:
Q1. 6 combinations
Q2. 2 combinations

Answer 9

I am getting Q1: 15, Q2: 7 as well.
I had to draw an image to visualize how it worked, which is attached. lol

Answer 10

why you call it a FOOL's problem I think it should be Einstein's problem

Answer 11

Ya @Glen_McGrath

Answer 12

I'm getting Q1 = 24.
Q2 = 7. May be wayy off.