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OpenStudy (anonymous):
Questions & Anwsers!?
1...6x/7-x/2 =5
x = 10
x = 5
x = 14
2...3/x-1 + 2/x =4
{0.25, 2}
{1/2, 2}
{1/2, 2}
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jimthompson5910 (jim_thompson5910):
# 1
6x/7-x/2 =5
14*6x/7-14*x/2 = 14*5
2*6x-7*x = 70
12x-7x = 70
5x = 70
x = 70/5
x = 14
jimthompson5910 (jim_thompson5910):
Basic idea: multiply everything by the LCD to clear out the fractions. Then solve like normal
jimthompson5910 (jim_thompson5910):
Use the same idea to solve #2
jimthompson5910 (jim_thompson5910):
Let me know how it goes
OpenStudy (anonymous):
i got 1
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jimthompson5910 (jim_thompson5910):
Is the problem in #2
\[\Large \frac{3}{x-1}+\frac{2}{x} = 4\]
???
OpenStudy (anonymous):
ya
jimthompson5910 (jim_thompson5910):
This one is trickier than I thought, one moment
OpenStudy (anonymous):
ok i got 1/2 and 2
jimthompson5910 (jim_thompson5910):
I'll show you how to do this one
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OpenStudy (anonymous):
Ok
jimthompson5910 (jim_thompson5910):
\[\Large \frac{3}{x-1}+\frac{2}{x} = 4\]
\[\Large 3x+2(x-1) = 4x(x-1)\]
\[\Large 3x+2x-2 = 4x^2-4x\]
\[\Large 5x-2 = 4x^2-4x\]
\[\Large 0 = 4x^2-4x-5x+2\]
\[\Large 0 = 4x^2-9x+2\]
\[\Large 4x^2-9x+2 = 0\]
\[\Large (x-2)(4x-1) = 0\]
\[\Large x-2=0 \ \text{ or } 4x-1=0\]
\[\Large x=2 \ \text{ or } x=\frac{1}{4}\]
So the solution set is {0.25, 2}
since 1/4 = 0.25
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