In the system shown below, what are the coordinates of the solution that lies in quadrant II?
Write your answer in the form (a,b) without using spaces.

x^2+4y^2=80
y= 1/32x^2

Question

In the system shown below, what are the coordinates of the solution that lies in quadrant II?
Write your answer in the form (a,b) without using spaces.
  
x^2+4y^2=80
y= 1/32x^2

apoorvk · Answer

is that y = (1/32)x^2 ?? If yes then...

from the second equation,

x^2 = 32 y

substitute this value for "x^2" in the first equation. You get:
32y^2 + 4y^2  = 80

Solve this^, get your (a,b) and the find out the quadrant!

apoorvk · Answer

I mean find out which root lies in the second quadrant. the 2nd quadrant has the abscissa(x-coordinate) negative and the ordinate(y-coordinate) positive.

anonymous · Answer

So when I solve for y in 32y^2 + 4y^2 = 80, I end up dividing 80 by 36 and then finding the square root of that, which ends up as a very messy number, correct? 
Which then turns the whole problem into a bit of a nightmare! Have I interpreted something incorrectly, or is this just a messy problem?

apoorvk · Answer

just a stupid messy problem, I guess. don't forget square roots will have have both the plus and minus values for 'y'.
should get: y = +sqrt(20/9) and -sqrt(20/9)

just confirming, which one is the second equation from below (am still doubting)|dw:1339047029977:dw|