Question

simplify by expressing fractional exponents instead of radical 8root of x^2 y^4

Answer 1

\[8\sqrt{x^2y^4}=8(x^2y^4)^{\frac{1}{2}}\]

Answer 2

Just use properties of exponents: \[(a^b)^c=a^{bc}\]

Answer 3

I tried it anf I still don`t get it, it gave me 8(abs(^nee) sq. rt of y^4 I`m lost

Answer 4

still need help?

Answer 5

yeaah D:

Answer 6

do you understand \(\large (a^b)^c = a^{bc} \) ?

Answer 7

yes

Answer 8

ok... so,
\(\huge 8\sqrt{x^2y^4}=8(x^2y^4)^\frac{1}{2}=8(x^2)^\frac{1}{2} (y^4)^\frac{1}{2} \)
\(\huge 8(x^{2\times\frac{1}{2}})(y^{4\times\frac{1}{2}}) \)

Answer 9

can you simplify it from here?

Answer 10

I`m not sure... or the first one I get 8 and for the second one I get y^2, would it be 8y^2?

Answer 11

*for

Answer 12

umm.... actually, this is what I should have shown..