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Physics 19 Online
OpenStudy (anonymous):

A man jumps 8.95 meter,travelling at 10 meters/second when he started his jump, we also know thatit took him 0.895s ... assuming that he undergoes a perfect projectile motion by ignoring air resistance and his body movements while in the air, what was the maximum height of his centre of mass from the ground? this should be the answer 0.98 m but could someone please explain how this was found :/ (this is not my H/w I'm studing for my exam)

OpenStudy (yash2651995):

you have been given time of flight and rangeput the values in respective formulas get value of u and angle of projection then find Hmax =usin☼^2/2g

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