Question

sqrt(3) divided by sqrt (12)-sqrt(3)=??

Answer 1

hint \[\sqrt {12} = \sqrt 3 \times \sqrt 4\] does that give you any ideas @nhernandez6 ??

Answer 2

I know that 3*4 would be 12 but im not sure on how to work it out

Answer 3

you have:\[\sqrt{3}/(\sqrt{12}-\sqrt{3})\]
multiply by \[(\sqrt{12}+\sqrt{3})/(\sqrt{12}+\sqrt{3})\]The denominator should cancel out, and you get 15 as your new denominator. For the numerator, you get \[\sqrt3(\sqrt{12}+\sqrt{3}) = \sqrt{36} + 3 = 6 + 3 = 9\]
and 9/15 = 3/5

Answer 4

so 3/5 would be the final answer?

Answer 5

Yep.

Answer 6

one question how did u get the 15?

Answer 7

Thanks a bunch

Answer 8

\[(\sqrt{12}-\sqrt{3})(\sqrt{12}+\sqrt{3})=(\sqrt{12})^{2}-(\sqrt{3})^{2}=12-3=9\]

Answer 9

Oops, my bad.

Answer 10

so 9/9=1

Answer 11

\[\frac{\sqrt{ 3 }}{ \sqrt{ 12 }-\sqrt{ 3 } }\\\\= \frac{\sqrt{ 3 }}{ \sqrt{4*3}-\sqrt{ 3 } }\\\\= \frac{\sqrt{ 3 }}{ 2\sqrt{ 3 }-\sqrt{ 3 } }\\\\= \frac{\sqrt{ 3 }}{ \sqrt{ 3} }\\=1 \]