I really need help with this one: You need a 10% alcohol solution. On hand, you have a 490 mL of a 5% alcohol mixture. You also have 80% alcohol mixture. How much of the 80% mixture will you need to add to obtain the desired solution? You will need ____mL of the 80% solution to obtain ____mL of the desired 10% solution.

Question

I really need help with this one: You need a 10% alcohol solution. On hand, you have a 490 mL of a 5% alcohol mixture. You also have 80% alcohol mixture. How much of the 80% mixture will you need to add to obtain the desired solution? You will need ____mL of the 80% solution  to obtain ____mL of the desired 10% solution.

anonymous · Answer

35 ml of 80% solution to prepare 525 ml of 10% solution

seattle12345 · Answer

would you mind showing me how you came up with that?

hero · Answer

Giving answers only is not allowed on OS

asnaseer · Answer

ok, you are given that 5% of 490 mL is alcohol.
this implies that the amount of alcohol in this solution is:$$\frac{5}{100}*490\text{ mL}$$agreed?

seattle12345 · Answer

yes agreed

hero · Answer

I could show you how to do this easy as pie

seattle12345 · Answer

lol ok. how?

hero · Answer

Hold on for just a minute