Question

f(x)=(x+2)^2-4
vertex?
minimum value is f(x)=?

Answer 1

y = (x+2)^2 - 4
y +4 = (x+2)^2

(x+2)^2 = y+4

(x-h)^2 = y-k (standard form) where (h, k) is the vertex

so the vertex is at (-2, -4)

Answer 2

the minimum would be the vertex in this case since it is extending upward. so f(x) = -4

Answer 3

(at x = -2)