Ask your own question, for FREE!
Chemistry 23 Online
OpenStudy (anonymous):

HELP ME <3 If 5.8 moles of nitrogen monoxide (NO) react with 10.0 moles of oxygen gas (O2), how many moles of the product can be formed and how many moles of the excess reactant will be left over when the reaction is complete? Show all of your work. unbalanced equation: NO + O2 --> NO2

OpenStudy (btaylor):

1. balance the equation: 2 NO + O2 --> 2 NO2 now, if 5.8 mol of NO is used, it would consume 2.9 mol of O2. So there is 7.1 mol O2 left over.

OpenStudy (anonymous):

But what I don't understand how to do that. How did you get 7.1? @BTaylor

OpenStudy (btaylor):

You have 10 mol O2 at the start. You use 2.9. So you have 10-2.9 = 7.1 mol left over.

OpenStudy (anonymous):

No way. Was it that simple? -___-

OpenStudy (anonymous):

@BTaylor

OpenStudy (btaylor):

yup.

OpenStudy (anonymous):

But where did the 2.9 come from? @BTaylor

OpenStudy (btaylor):

for every mol of NO used, you use half a mole of O2. So multiply 5.8 by 0.5, and you get 2.9

OpenStudy (anonymous):

oh okay thank you (:

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!