The equation of a circle is shown below.
(x – 1)2 + (y + 3)2 = 16
Which statement is true about the center of the circle?
It is located on the x-axis.
It is located on the y-axis.
It is located in the third quadrant.
It is located in the fourth quadrant.
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OpenStudy (lgbasallote):
do you know the coordinates of the center?
OpenStudy (anonymous):
No I do not.
OpenStudy (lgbasallote):
look at \((x-1)^2 + (y+3)^2\)
if you equate x-1 to 0 you get x - 1 = 0
can you solve for x?
OpenStudy (anonymous):
1
OpenStudy (anonymous):
The center is (1, -3) so it's in the fourth quadrant
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OpenStudy (lgbasallote):
x = 1 that's right...therefore the x coordinate of the center is at 1
to find the y coordinate just equate y + 3 to 0
OpenStudy (anonymous):
Thank you, but how did you come by this?
OpenStudy (lgbasallote):
just follow the instructions im giving :D
OpenStudy (anonymous):
I am
OpenStudy (lgbasallote):
i know ^_^
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OpenStudy (lgbasallote):
so solve for y in y + 3 = 0
OpenStudy (anonymous):
-3?
OpenStudy (lgbasallote):
yup...therefore y coordinate of center is -3
so the point of the center is (1,-3)
positive x...negative y
OpenStudy (anonymous):
fourth quadrant
OpenStudy (lgbasallote):
|dw:1339115121728:dw| that is the cartesian plane
fourth quadrant is correct