Question

split de middle term nd find itz linear factors,
7y^2-(11/3)y-2/3

Answer 1

@apoorvk

Answer 2

@ParthKohli

Answer 3

let's multiply the whole thing by 3 to make it easier.

Answer 4

so do v get...21y^2-11y-2??

Answer 5

yes!, but since I have multiplied this by '3', i would multiply the RHS by 3 as well. But the RHS is '0'. So, 3 x 0 = 0
hence no probs with the multiplication!

now split the middle term..

Answer 6

product=-42, sum -11. giv me de middle termz no

Answer 7

product or sum is not needed in this case.

21y^2-11y-2 = 0

factors of 21 are 7 and 3, and factor of 2 is 2 itself.

so, I have these factors of the equations's 'a' and 'c' --> 3,7,2

now let me group this into two such that deducting them would give me 'b', i.e. '-11'

I think 7,2 in one, and 2 in another should work. what say?

Answer 8

k

Answer 9

Understandable?

Answer 10

yup u r awsome dude

Answer 11

wht

Answer 12

Loooll!!

you are more awesome, Lady!

Answer 13

no i am very week in maths

Answer 14

bt i admire u

Answer 15

i mean i made a mistake in the last line of the the solution

*CORRECTION*

I mean - "I think 7,2 in one, and *3 in another"

Answer 16

anyway k i'll do dnt worry

Answer 17

No, I think you're 'weak' in English, not maths :P :P

Answer 18

anyway gud frenz 4 ever

Answer 19

u in 12th

Answer 20

jus' kiddin. :p
Your understanding power is great, as is your attitude. Keep it up :)

Yes! :)

Answer 21

thx me in 10th
where is ur huse

Answer 22

No, I mean 'yes' was for your post above.

I have cleared 12th actually.

Answer 23

k where is ur huseeeeeee