Question

2.Identify the asymptotes of the graph. y=1/x-2-3

Answer 1

All asymptotes or just vertical ones?

Answer 2

yea

Answer 3

lol, vertical asymptotes or All asymptotes? You didn't answer my question.

Answer 4

what do you mean

Answer 5

you can have vertical asymptotes and horizontal asymptotes, I'm just not sure what you have learnt. So I'm trying to find out.

Answer 6

here is one of the graph

Answer 7

Ok so to find vertical asymptotes, we just equate the equation at the bottom to zero and solve for x.
Because any number divide by zero goes to infinity.
So for this one, we want to find when \[1/ x-2\] goes to infinity, so we do \[x-2=0\]
\[x=2 \]is your vertical asymptote

Answer 8

yea and whats for y

Answer 9

To find horizontal asymptotes, we need to first write our equation in standard form first

Answer 10

and then figure out what the fraction approaches to as x gets huge

Answer 11

Vertical asymptotes occur when the denominator equals 0. What value of x makes it 0? 2.
x = 2
Horizontal asymptotes. If the degree is bigger on the bottom, the asymptote is always at y = 0 However, it says + 3 which is a vertical shift. THerefore, it's y = 3.
For more info, if the degrees are the same, take the ratio of the leading coefficients to get the asymptote. If the top is bigger than the bottom by one, then it's an oblique asymptote.

Answer 12

thanks everybody

Answer 13

If the exponent in the denominator of the function is larger than the exponent in the numerator, the horizontal asymptote will be y=0.
If there is a bigger exponent in the numerator of a given function, then there is NO horizontal asymptote.

Answer 14

No problem.