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Mathematics 21 Online
OpenStudy (anonymous):

Find the orthogonal trajectories of the family of curves. (Use C for any needed constant.) x^2 + 2y^2 = 14k^2 Help understanding and working out. Tried solving for dy/dx and than putting that under -1 resulting in 2y/x but that didn't result in the correct solution...

OpenStudy (anonymous):

replace dy/dx by -dx/dy and then u can derive the result

OpenStudy (anonymous):

is the ans x2=cy

OpenStudy (anonymous):

Isn't that the same as -1/(dy/dx)? B/c I took the derivative across the whole equation and got 2x+4y (yd/dx) = 0 then I solved for dy/dx and got 2x/-4y. so for the answer as to the orthoginals I thought id be... -1/(2x/4y)

OpenStudy (anonymous):

Okay, so that should be... 2y/x again... am I supposed to integrate this or something?

OpenStudy (anonymous):

u should integrate back

OpenStudy (anonymous):

Wow, kinda silly that I didn't remember that...

OpenStudy (anonymous):

sometimes it happens

OpenStudy (anonymous):

Uck... it's still wrong though... -_-

OpenStudy (anonymous):

is it y=cx^2

OpenStudy (anonymous):

How did you get that though?

OpenStudy (anonymous):

arrange for constant

OpenStudy (anonymous):

What?

OpenStudy (anonymous):

So, solve for y first?

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