Mathematics
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OpenStudy (anonymous):
Please! $15,000=$7,500(1+.0015/12)^12t... solve for "t"
13 years ago
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OpenStudy (anonymous):
\[\large 15000=7500(1+0.0015)^{12t}\rightarrow 2=(1.0015)^{12t} \]
13 years ago
OpenStudy (anonymous):
so to solve for t:
13 years ago
OpenStudy (anonymous):
\[\large ln2=(12t)(ln1.0015) \]
can you take it from here?
13 years ago
OpenStudy (anonymous):
what's "ln"?
13 years ago
OpenStudy (anonymous):
natural log...
13 years ago
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OpenStudy (anonymous):
logarithm base e
13 years ago
OpenStudy (anonymous):
you really don't need ln... you can use common log.. log base 10
13 years ago
OpenStudy (anonymous):
I have not learned that yet... so I have no idea what to do after that :/
13 years ago
OpenStudy (anonymous):
how about common logs? log base 10?
13 years ago
OpenStudy (anonymous):
I don't know :(
13 years ago
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OpenStudy (anonymous):
hmmm... that's strange that you're asked to solve for "t" without knowing about logarithms.
13 years ago
OpenStudy (anonymous):
it's an online class :/
13 years ago
OpenStudy (anonymous):
oh... so did the class go through logarithms?
13 years ago
OpenStudy (anonymous):
no
13 years ago
OpenStudy (anonymous):
is it an online math class or online business class?
13 years ago
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OpenStudy (anonymous):
Advanced Math with Financial Applications
13 years ago
OpenStudy (anonymous):
hmm... seeing those words advanced and financial makes me think they're assuming you already know about logarithms...
13 years ago
OpenStudy (anonymous):
I don't
13 years ago
OpenStudy (anonymous):
the only thing i can tell you here is that in order to solve for t in your question, you'll need to use logarithms...:(
13 years ago
OpenStudy (anonymous):
Well can you at least tell me how to input it in my calculator or something? or the link to a website that can teach about logarithms?
13 years ago
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OpenStudy (anonymous):
sure...:)
let's solve for t first on that last line I left you with...
13 years ago
OpenStudy (anonymous):
\[\large ln2=(12t)(ln1.0015)\]
\[\large \frac{ln2}{12ln1.0015}=t\]
13 years ago
OpenStudy (anonymous):
ok... you have your calculator?
13 years ago
OpenStudy (anonymous):
do you see a "ln" button?
13 years ago
OpenStudy (anonymous):
or "log" button?
13 years ago
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OpenStudy (anonymous):
yes
13 years ago
OpenStudy (anonymous):
it doesn't matter which one you use... "ln" or "log"
13 years ago
OpenStudy (anonymous):
what did you get?
13 years ago
OpenStudy (anonymous):
I don't think its the right answer considering t stands for time :/... .000086578
13 years ago
OpenStudy (anonymous):
no.... i got something else...
13 years ago
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OpenStudy (anonymous):
does your calculator allow you to use parenthesis?
13 years ago
OpenStudy (anonymous):
yes
13 years ago
OpenStudy (anonymous):
good...
make sure you enter: (ln2)/(12*ln1.0015)
13 years ago
OpenStudy (anonymous):
38.54?
13 years ago
OpenStudy (anonymous):
yep... that's what i got...:)
13 years ago
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OpenStudy (anonymous):
YESSS! Thank you soo much!!!
13 years ago
OpenStudy (anonymous):
yw...:)
13 years ago
OpenStudy (anonymous):
you have a kweschun?
13 years ago
OpenStudy (anonymous):
You know how the original formula was : 15,000 = 7,500 (1 + .0015/ 12) ^12t... Well I'm writing it in my report and I saw we solved the logarithm of 1.0015 instead of 1.000125 which is the (1 + .0015/ 12) part :/
13 years ago
OpenStudy (anonymous):
\[\large 15000=7500(1+\frac{0.0015}{12})^{12t}\rightarrow 2=(1.0013)^{12t} \]
13 years ago
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OpenStudy (anonymous):
\[\large 15000=7500(1+\frac{0.0015}{12})^{12t}\rightarrow 2=(1.00013)^{12t} \]
13 years ago
OpenStudy (anonymous):
Ok I did the same thing ... now I got 462 years? roughly?
13 years ago
OpenStudy (anonymous):
i got 444.354 years
13 years ago
OpenStudy (anonymous):
Ok I used 1.000125 not 1.00013 ... would that matter?
13 years ago
OpenStudy (anonymous):
haha...yours is more accurate...:)
13 years ago
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OpenStudy (anonymous):
I'm ok with that haha, thanks again!
13 years ago
OpenStudy (anonymous):
yw...:)
13 years ago