Question

Find the area of the region. Use a graphing utility to verify your result. y = 6 sin(x) + sin(6x)

Answer 1

\[\int_{0}^{\pi}6 sin(x)+sin(6x)dx\]

Answer 2

so would I split it up into 2 integrals and solve for each? What would x be? :(

Answer 3

you could split it up but don't need to

Answer 4

so just integrate as is?

Answer 5

\[\int\limits -6\cos(x) -\frac{\cos(6x)}{6}\] ???

Answer 6

err nvm the integration sign and add the 0 to x?

Answer 7

and what do I dooo for x? Apparently it can be 0 to pi?

Answer 8

\[[-6\cos(\pi) - \frac{\cos(6\pi)}{6} ] - [-6\cos(0) - \frac{\cos(0)}{6} ]\]

Answer 9

thats it

Answer 10

[6 - (1/6)] - [6 - (1/6)]?

Answer 11

so I could do 36/6 - 1/6 = 35/6 - 35/6 = 0?

Answer 12

I think I messed up :(

Answer 13

err it would be 35/6 + 35/6 = 70/6?

Answer 14

Nope that's not right :(

Answer 15

[-6(-1)-1/6]-[-6-1/6]

Answer 16

-6cos(pi)-cos(6pi)/6=(6-1/6)
-6cos(0)-cos(0)/6=(6-1/6)
(6-1/6)-(6-1/6)=12
calclus problem

Answer 17

Should be (6-1/6)-(-6-1/6)=12

Answer 18

SOO TIRED. Thanks all for oyur help :)