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How many grams of magnesium oxide can be produced when 125 g Mg react with 102 g O2?
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1)To answer this kind of question, firstly you have to write down the equation of the reaction. 2) then you have to compare the number of moles between the reactants and the product. 3) and then you determine the limiting factor. 4) You multiply the moles of the limiting factor with the molar mass of MgO and you'll get the answer.
The equation of the reaction is Mg + O2 --> MgO but you have to balance it so it becomes 2Mg + O2 --> 2MgO
Um if I'm not mistaken the answer is 255g?
I use R.A.M of Mg = 24 to get 255 g of MgO If you use R.A.M of 24.3 you ought to get 207.3 g of MgO. Mg will be the limiting factor.
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