Question

The equation of a circle is shown below.

(x – 3)2 + (y – 2)2 = 9

Which statement is true about the center of the circle?

It is located on the y-axis.

It is located in the third quadrant.

It is located in the first quadrant.

It is located on the x-axis.

Answer 1

Do you have a graphing calculator?

Answer 2

Or graph paper?

Answer 3

i have geogebra on my computer!

Answer 4

very nice, so do I, and I love it lol

Answer 5

simply type (x-3)^2 + (y-2)^2 = 9 into the input bar and it will graph the circle

Answer 6

lol me to!!! ...it doesnt do a circle tho it does a line

Answer 7

remember to type ^

Answer 8

It's NOT (x – 3)2 + (y – 2)2 = 9 it's really (x-3)^2 + (y-2)^2 = 9

Answer 9

oo ok hold on ill redo it! lol

Answer 10

ok

Answer 11

ok now i have a circle! lol

Answer 12

yay

Answer 13

so where is the center?

Answer 14

is this right??? ....It is located in the first quadrant.

Answer 15

optionally, you can type "center(c)" without quotes and it will plot out the center point

Answer 16

you got it

Answer 17

wait no ...ummm this one right?? ....It is located on the x-axis.

Answer 18

no, did you type "center(c)"?

Answer 19

into the input bar

Answer 20

oh and don't enter the quotes

Answer 21

i didnt know it could do that! lol ...center is (3,2)

Answer 22

perfect

Answer 23

btw, if you can't use a graphing calculator or geogebra, then you can look at the equation

(x-3)^2 + (y-2)^2 = 9


and notice that it's in (x-h)^2+(y-k)^2=r^2 form


Since h = 3 and k = 2, the center is (3,2)

Answer 24

ok...so whats the answer then?

Answer 25

where is (3,2)? is it on the x-axis or in the first quadrant?

Answer 26

ummm first quadrant??

Answer 27

you got it

Answer 28

so the center is in the first quadrant

Answer 29

your first answer was right on, so it's always good to go with your instinct

Answer 30

ok yay! lol ...thanks!!!!

Answer 31

yw