Question

cos^2 x + sinx+1 = 0

Answer 1

\[\text{ use } \cos^2(x)=1-\sin^2(x)\]

Answer 2

Put it in terms of one trig function
By using the identity I mentioned above you can do this

Answer 3

o okay so all cosine

Answer 4

\[\text{ since } \cos^2(x)=1-\sin^2(x) \text{ then you can replace } \cos^2(x) \text{ with }\]
\[1-\sin^2(x)\]

Answer 5

So it will be in terms of sine not cosine

Answer 6

oh ok can u help me with something else while ur here

Answer 7

\[1-\sin^2(x)+\sin(x)+1=0\]
Do you see that I just replaced \[\cos^2(x) \text{ with } 1-\sin^2(x)\]

Answer 8

yaaa i remmeber tha rule from class

Answer 9

ok so if i have cos x = -0.438

Answer 10

So this is a different question?

Answer 11

is that the reference angle?

Answer 12

ya

Answer 13

So you want to find x right?

Answer 14

wait so do i type it in calc and that ALWAYS gives me the angle in quadrant 1?