By using stokes' theorem evaluate:
by using stokes' theorem: \[\int\limits_{c}^{}F.dr=\int\limits_{}^{}\int\limits_{s}^{}(\Delta \times F).nds\] evaluate \[\int\limits_{}^{}\int\limits_{s}^{}(\Delta \times F).nds\] where \[F=(x,1,-y^{2})\] and S is the outward part of the surface \[x ^{2}+4y ^{2}+3z ^{2}=7\] that lies above the plane \[z=1\]
@AndrewNJ
@apoorvk
please help
@lgbasallote
I am sorry @Tushara but I haven't studied this advanced or multi-variable calculus yet, and don't have much idea of 'delta' and all. Won't be able able to help here :( Perhaps @lalaly or @lgbasallote will know this.
thats ok, thanks for trying
lol @apoorvk
@A.Avinash_Goutham
um wat's the problem? it looks simple
integrate it along the curve x2+4y2+3(1)=7 x2+4y2=4
i think the ans is 1
no the answer is zero, its ok, i figured it out :)
yea it's zero sorry
@A.avinash_Goutham - could you please explain a wee bit what we are doing here? I am just a bit curious..
um wat do u want to kno?
the same question is done as an example on dis page: its example one, and delta F is equivalent to the curl of F http://tutorial.math.lamar.edu/Classes/CalcIII/StokesTheorem.aspx
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