solve the equation:
2 x 10^(2-x)=5?

Question

solve the equation:
2 x 10^(2-x)=5?

mathslover · Answer

$$2* 10^{2-x} = 5$$
$$2* [2^{2-x} * 5^{2-x}] = 5$$
$$2 * 2^{2-x} * 5^{2-x} = 5$$
$$2^{2-x+1} * 5^{2-x}=5$$
$$2^{3-x} = 5/5^{2-x}$$
$$2^{3-x} = 5^{1-2+x}$$
$$2^{3-x} = 5^{x-1}$$

mathslover · Answer

wait i am solving it more

maheshmeghwal9 · Answer

Answer must be in Log form^_^

anonymous · Answer

Yeah the answer is 2-log5/2 i just cant figure out how to get it :(

unklerhaukus · Answer

$$2 \times 10^{2-x}=5$$$$10^{2-x}=\frac 52$$$$\log_{10}10^{2-x}=\log_{10}\frac52$$$$(2-x)\log_{10}10=\log_{10}5-\log+_{10}2$$$$2-x=\log_{10}5-\log+_{10}2$$$$x=\cdots$$

unklerhaukus · Answer

*
$$2-x=\log_{10}5-\log_{10}2$$
$$2-x=\log_{10}\frac52$$

unklerhaukus · Answer

$$x=$$

anonymous · Answer

so then -x=-2+log5/2
x=2-log5/2!

lgbasallote · Answer

lol why did you make it complicated @mathslover :P hahah lol :)

anonymous · Answer

I know I got lost there they prob did too lol

mathslover · Answer

@lgbasallote  every thing is complicated in the life lolz 

actually i am not perfect in Logarithm sorry

lgbasallote · Answer

your steps are actually interesting..amazing manipulations and mastery of the rules on exponents

mathslover · Answer

:) thanks but i dont think that they will help in this question