1. Solve: y2 + 7x = 30 2. Solve: x2 + 7 = -8x 3. Solve: x2 – 26x + 48 = 0 4. Solve: x2 - 4x = 32 5. Solve: w(6w + 12) = 0 6. Solve: y2 + y = 30 7. Solve: (a – 5)(a + 3) = 0
That's a lot to solve hehe!
Do you know anything about quadratic equations?
No not really
All right. You're ready to embark on a journey :)
There are infinite number of ways to solve a quadratic equation, but you may use the formula to start.
A quadratic equation looks like: \(ax^2 + bx + c = 0\) It has 2 number of solutions(maximum)
ok
And the formula to solve for \(x\) is: \( \color{Black}{\Rightarrow \Large x = {-b \pm \sqrt{b^2 - 4ac} \over 2a} }\)
right ..
Do you know what \(\pm\) means?
yess
Yes, anyway, it means that x as two solutions: \( \color{Black}{\Rightarrow \Large {x = {-b + \sqrt{b^2 - 4ac} \over 2a}} }\) OR \( \color{Black}{\Rightarrow \Large x = {-b - \sqrt{b^2 - 4ac} \over 2a} }\)
right soo then i just plug in ?
yep.
Thanks
There's another thing here. The zero product rule.
oh whats that ?
Some of them are given like (a - 5)(a + 3) = 0 Zero product rule says that if a * b = 0, then either a = 0 or b = 0
This is because any number multiplied by 0 is 0! :)
So for example \((a - 5)(a + 3) = 0 \) Either a - 5 is 0 or a + 3 is 0. We can equate.
\( \color{Black}{\Rightarrow a - 5 = 0 }\) \( \color{Black}{\Rightarrow a = 5 }\) OR \( \color{Black}{\Rightarrow a + 3 = 0 }\) \( \color{Black}{\Rightarrow a = -3 }\)
Ohh I get it . that means the problem cant be solved ?
It can be solved.
That's when another method known as factorization comes in, though it may be difficult for me to explain.
Did you get that (a - 5)(a + 3) = 0 example I gave you?
Yes I get it . (:
Aha! Is there anything left for me to explain?
i think i have the hang of it . (: Thankyou SoMUCH !
You're welcome :)
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