N(x)=100+20*ln(0.25x)
explanation in comments
please look

Question

N(x)=100+20*ln(0.25x)
explanation in comments
please look

anonymous · Answer

he number of computers sold by Bcc depends on dollar mountx, that they spend on advertising. how many computers will they sell by spending 40000 dollars

anonymous · Answer

284?

kropot72 · Answer

Yes. The correct answer is 284 computers.

anonymous · Answer

@kropot72  N(x)=100+20*ln(0.25x). the number of computers sold by bcc depends on dollar amount x, that they spend on advertising. how much do they spend to get 200 computers? how would i do this one

kropot72 · Answer

200 = 100 + 20 * ln(0.25x)
200 - 100 = 20 * ln(0.25x)
$$\frac{200-100}{20}=\ln (0.25x)$$
5 = ln(0.25x)
Can you solve it now?

anonymous · Answer

@kropot72 maybe im still a little confused

kropot72 · Answer

5 = ln(0.25x)
$$e ^{5}=0.25x$$
$$x=\frac{e ^{5}}{0.25}$$

anonymous · Answer

@kropot72 593.34

kropot72 · Answer

My calculator gives $593.65

anonymous · Answer

@kropot72 did you use 2.718 for e

kropot72 · Answer

No. When I enter e^1 on my calculator it gives the value of e to 9 decimal places.

anonymous · Answer

ohh ok for my quwstion we are just required to use 2.718 @kropot72

kropot72 · Answer

Understood. In that case your answer should be marked as correct :)

anonymous · Answer

298 is the correct answer for this problem.