The figure below shows rectangle ABCD. The two-column proof with missing statement proves that the diagonals of the rectangle bisect each other. Statement Reason ABCD is a rectangle. Given and are parallel Definition of a Parallelogram and are parallel Definition of a Parallelogram Alternate interior angles theorem Definition of a Parallelogram ∡ADB ≅ ∡CBD Alternate interior angles theorem Angle-Side-Angle (ASA) Postulate CPCTC CPCTC bisects Definition of a bisector Which statement can be used to fill in the blank space? ∡ABD ≅ ∡DBC ∡CAD ≅ ∡ACB ∡BDA ≅ ∡BDC ∡CAB ≅ ∡ACB
can I get a screenshot of the statements and reasons please?
how do i do that?
are you using a windows or a mac?
windows
Look at the table you want to capture, then hit the "printscreen" button (located above the insert key). Then open up MS paint. From there, hit "paste" and save
try this!
ok one sec
ok that works, thx
hmm which statement line is blank, they all look filled to me...I must be missing something lol
oh wait, spoke too soon, I see it
haha ok
The first and last choices aren't the answer because they form complementary angles, so they aren't equal. This means that choice B is really the answer and it turns out to be a legitimate argument as well.
o ok thanks! ...<3
sure thing
It's the second one.
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