Question

You randomly pick two marbles from a bag containing 3 yellow marbles and 4 yellow marbles and 4 red marbles. you pick the second marble without replacing the first marble. find each probability. 1. p(red then red) 2. p(yellow then red)

Answer 1

wait so theres 7 yellows?

Answer 2

no 3 sorry forget the 4 yellow marbles

Answer 3

haha ok so grabbing a red is 1/7 right? nd no replace ment makes the next marble 1/6 so if i remember correctly you multiply these nnumbers

Answer 4

ok

Answer 5

i could be wrong, im doubting nmyself...

Answer 6

ima check with a friend...

Answer 7

stupid friend no answer phone.

Answer 8

i think your right

Answer 9

ummm ithink so but doubts

Answer 10

try

Answer 11

oops made a typo

Answer 12

ok @jim_thompson5910 got it right.

Answer 13

P(red then red) = P(red)*P(red)


P(red then red) = (4/7)*(3/6)


P(red then red) = 12/42


P(red then red) = 2/7

Answer 14

the answer is that be cause yu have 4 out of 7 reds, ns once you take out yu now have 3 of the the 6(yu lost one)

Answer 15

P(yellow then red) = P(yellow)*P(red)

P(yellow then red) = (3/7)*(4/6)

P(yellow then red) = 12/42

P(yellow then red) = 2/7

Answer 16

haha wrong answer the first time but i understood it @jim_thompson5910

Answer 17

so in this case, the probabilities are the same