is this correct? problem => (1/8x^2 - 1/4x - 3/8) + ( -1/2x^2 - 1/4x - 1/2) my answer is => 17.5x^2 - 1/2x - 7/8
Check your first term
should it be -17.5 is that what ur asking?
Nope
Everything other than the first term is correct. 1/8 - 4/8 = -3/8
\[\frac{1}{8}-\frac{1}{2}\] Common denominator is 8 \[\frac{1}{8}-\frac{1*4}{2*4}\]
i am lost then what are the steps? tonight, has not been a math noght (smiling)
and what @Calcmathlete got... :)
lol we just posted it... everything else is corrected just ignore the variable for a second and focus on the fractions... and work them like your working regular numbers and then plug back in your variables
\[(\frac{1}{8}x^2 - \frac{1}{4}x - \frac{3}{8}) + ( -\frac{1}{2}x^2 - \frac{1}{4}x - \frac{1}{2}) \] Okay so.. -1/4-1/4 = -2/4 and -3/8-1/2 =\[-\frac{3}{8}-\frac{1*4}{2*4}\] =\[-\frac{3}{8}-\frac{4}{8}\] =\[-\frac{7}{8}\]
boy am i way off..
Do you understand where you went wrong @fuzzyspawn though?
y did the calculator give me the numbers i put down?
i wont be using the calculator anymore i will go back to long hand.
I was using the polinomial calculator from online someone reccommended
polynomial
Hmm, I don't trust my calculator sometimes with fractions... did you use a lot of brackets because some calculators require more than others. Try putting it in like this and let me know what you get (1/8)-(1/2)
No... it might cost you to loose time on exams, test and quizzes.
Oh... hmm, well computer's do have some faults so Idk
\[(1/8x{}^{\wedge}2-1/4x-3/8)+(-1/2x{}^{\wedge}2-1/4x-1/2)=-\frac{3 x^2}{8}-\frac{x}{2}-\frac{7}{8} \]
But that should only be used as a check have you tried wolfram alpha? I in most instances don't go wrong there.
i havent heard about that one site, is it good?
Yes it is...
cool then i will try it I appreciate your help! getting (math headache) gonna get back later thanks
Okay, no problemo!
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