x+2/6 = 2/x-1 pleaseeeee help me !
Is this the problem: \[\frac{x + 2}{6} = \frac{2}{x - 1}\]
yess
Just cross multiply. \[(x + 2)(x - 1) = 2(6)\] \[(x + 2)(x - 1) = 12\] \[x^{2} + x - 2 = 12\] \[x^{2} + x - 14 = 0\] Can you solve the quadratic now?
no i forgot how to do that
Just solve using the quadratic formula: \[x = \frac{-b ± \sqrt{b^{2} - 4ac}}{2a}\] Where: a = 1 b = 1 c = -14
i learned it an easier way ,
what 2 #'s multpliy to 1 and add up to 14?
That's why we can't do that. There aren't any numbers that can work like that.
ohhhh got it, well we haven't learned that formula so i will leave it like that
Okay, complete the square? x^2+x−14=0 x^2+x=14 x^2+x+0.25=14+0.25 x+0.5=±3.77 Can you solve from here?
Arte you sure you haven't learned any of this stuff?
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