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OpenStudy (anonymous):
x+2/6 = 2/x-1 pleaseeeee help me !
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OpenStudy (anonymous):
Is this the problem:
\[\frac{x + 2}{6} = \frac{2}{x - 1}\]
OpenStudy (anonymous):
yess
OpenStudy (anonymous):
Just cross multiply.
\[(x + 2)(x - 1) = 2(6)\]
\[(x + 2)(x - 1) = 12\]
\[x^{2} + x - 2 = 12\]
\[x^{2} + x - 14 = 0\]
Can you solve the quadratic now?
OpenStudy (anonymous):
no i forgot how to do that
OpenStudy (anonymous):
Just solve using the quadratic formula:
\[x = \frac{-b ± \sqrt{b^{2} - 4ac}}{2a}\]
Where:
a = 1
b = 1
c = -14
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OpenStudy (anonymous):
i learned it an easier way ,
OpenStudy (anonymous):
what 2 #'s multpliy to 1 and add up to 14?
OpenStudy (anonymous):
That's why we can't do that. There aren't any numbers that can work like that.
OpenStudy (anonymous):
ohhhh got it, well we haven't learned that formula so i will leave it like that
OpenStudy (anonymous):
Okay, complete the square?
x^2+x−14=0
x^2+x=14
x^2+x+0.25=14+0.25
x+0.5=±3.77
Can you solve from here?
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OpenStudy (anonymous):
Arte you sure you haven't learned any of this stuff?
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