Question

Given the function f(x)=8Ix−2I, calculate the following values ,

f(-2)=
f(x+1)=
f(x^2+2)=

Answer 1

f(-2)=81*(-2)-21
=-162-21
=-183

Answer 2

M i correct???

Answer 3

no it's not 81 it's an apsolute value of x-2

Answer 4

I m in X. I was trying to help if I can but sorry:(

Answer 5

@apoorvk plz help

Answer 6

thanks for trying

Answer 7

yw:)))

Answer 8

@dpaInc, @Callisto , @UnkleRhaukus , @Calcmathlete Plz help:)

Answer 9

i'll do the first one....:)

Answer 10

oops it's been done...

Answer 11

wait... the first one i think is incorrect....

Answer 12

yes yes

Answer 13

\[f(x)=8|x−2|\] \[f(-2)=8|-2−2|\]\[f(x+1)=8|(x+1)-2|\]\[f(x^2+2)=8|(x^2+2)-2|\]

Answer 14

\(|z|\) means the absolute value of z
ie the magnitude of \(z\)
the length without sign

Answer 15

Replace x by the thing(s) in the bracket and simplify....

Answer 16

\[f(−2)=32\]
\[f(x+1)=8*|x-1| \]
\[f(x2+2)=8x^2\]
See if you get the same answers :)

Answer 17

thanks yall