a particle moves along the x axis. Its position as a function of time is given by x=6.8t + 8.5t^2, where t is in seconds and x in meters. what is the acceleration as a function of time?

Question

anonymous · Answer

differentiate the given function twice w.r.t time to get the acceleration of the particle as a function of time.
By the looks of it, the aceleration is a constant 17 m/s^2.

anonymous · Answer

but how do you differentiate? :/

anonymous · Answer

OK, so you haven't learnt differentiation?

anonymous · Answer

yeah, i haven't :s integrals too...

anonymous · Answer

OK, so you want to know so much diff so that you can solve this problem OR you want everything about differentiation?

anonymous · Answer

just this problem is okay, am sure it might be easier than a whole lesson, thank you for helping :)

anonymous · Answer

so if $$f(x)=ax ^{n}$$
where a & n are real numbers, then
$$d[f(x)]/dt =an(x)^{n-1}$$

anonymous · Answer

$$d(a constant)/dt = 0$$

anonymous · Answer

thank you :)