Question

integrate sec^2(2x)

Answer 1

integrate integrate? as in \(\iint\)?

Answer 2

= ln cos(2x)/4

Answer 3

cos^3/3 2x^2/2

Answer 4

It's not \(\frac{lncos(2x)}{4}\)
It's a standard integral.
\[\int\limits \sec^{2}adx = \frac{1}{a} secax +C\]

Answer 5

@hogr-eng fair warning..it's against the site rulesto give an answer only (although i am not sure if that is the right answer) just a heads up ^_^ the site'sgoal is to help people learn so explanations/solutions are very much required

that goes for you too @izanagi.wielder ;) hehe

if you need more info check this out! :DDD http://openstudy.com/code-of-conduct

Answer 6

k
but how will i show you the work of integration

Answer 7

Woops I made a typo:
\[\int\limits \sec^{2}adx = \frac{1}{2} tanax +C\]

Answer 8

And another typo lol
\[\int\limits \sec^{2}adx = \frac{1}{a} tanax +C\]

Answer 9

^typo .....\[\int\limits \sec^{2}axdx = \frac{1}{a} tanax +C\]

Answer 10

woops again xD

Answer 11

??

Answer 12

cant we just agree that \[\int \sec^2 u = \tan u\] lol...deriving new formulas :PP

Answer 13

Since \(\frac{d}{dx}tanax = asec^2ax\),

\(\int sec^2(ax) dx= \frac{1}{a}tan(ax)+C\)

Now, a = 2, I think @watson can get the answer from the above hint. If not, let us know.

@lgbasallote No, it should be \(\int sec^2u \ du\) for the left part...

Answer 14

lol that's understood :P

Answer 15

and also you've missed the '+C' for the right

Answer 16

lol perfectionists :p

Answer 17

int[int sex^2(2x)]= int[tan2x/2]= tan u/4 =ln(|cos u|)/4 ....... u=2x