A 50 kg crate rests on a horizontal ground for which the coefficient of friction is k =0.3.
A towing force of 400 N is applied to the crate at an angle of 300 to the horizontal. Find
the velocity of the crate in 5 s starting from rest.

Question

A 50 kg crate rests on a horizontal ground for which the coefficient of friction is k =0.3.
A towing force of 400 N is applied to the crate at an angle of 300 to the horizontal. Find
the velocity of the crate in 5 s starting from rest.

anonymous · Answer

$$a= (F _{1}-F _{2})/M$$
$$F _{applied}=400N$$    $$F _{f}=\mu F _{N}$$ $$F _{f}=(.3)(50)(9.8)$$

a=5.06m/s^2
v=at
v=25.3m/s

anonymous · Answer

so, we don't have to use the given angle ?