Question

Choose the equation below that corresponds to the graph shown.

y = −3x2 − 12x − 14

y = 3x2 + 12x − 14

y = −3x2 + 12x − 14

y = 3x2 − 12x − 14

Answer 1

(looked this up too)
ax^2+bx+c
if a>0, parabola opens up and has a min at the vertex
if a<0, parabola opens down and has a max at the vertex
b/(2a) will give the x-coordinate of your vertex
plug b/(2a) back into the function to get the y-coordinate

So the answer here is A, because it opens down and has a max,
and the x-coordinate of the vertex is 12/-6=-2
the y-coordinate of the vertex is: -3(-2)^2-12(-2)-14=

Answer 2

First 1

Answer 3

thanks guys

Answer 4

Anytime :)