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OpenStudy (anonymous):
Which expression is equivalent to -(x^-2)^-4
a) -1/x^8
b) 1/x^8
c) -x^8
d) x^8
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OpenStudy (anonymous):
c
mathslover (mathslover):
\[-(x^{-2})^{-4}\]
\[-(1/x^2)^{-4}\]
\[-(1^{-4})/(x^2*{-4})\]
\[-1/{x^{-8}}\]
\[x^8*-1\]
\[-x^8\]
c is the answer
OpenStudy (anonymous):
is (b)
OpenStudy (mertsj):
When you raise to a power, you multiply the exponents.
\[-(x ^{-2})^{-4}=-(x^8)=-x^8\]
OpenStudy (anonymous):
That's what the law of negative exponents states @Mertsj. It's say that to make it positive you have to flip it.
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OpenStudy (anonymous):
@mathslover the result will be like this\[-x^{-8} = -x ^{-8}\]
OpenStudy (anonymous):
so when it will go down the negative sign will change into positive
\[1 \over x ^{8}\]
mathslover (mathslover):
@izanagi.wielder i dont think that u r going on right way ...
- (x^-8) = -1/(-x^8)
OpenStudy (mertsj):
Stop being ridiculous. The answer is -x^8
OpenStudy (anonymous):
sorry :]
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OpenStudy (anonymous):
Oh and I mean to say that's not what the...
OpenStudy (mertsj):
\[-(x ^{-2})^{-4}=-(\frac{1}{x^2})^{-4}=-(x^2)^4=-x^8\]
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