Sketch the curve represented by the parametric equations (indicate the direction of the curve). Use a graphing utility to confirm your result. Then eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve
x=3-2t
y=2+3t

Question

Sketch the curve represented by the parametric equations (indicate the direction of the curve). Use a graphing utility to confirm your result. Then eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve
x=3-2t
y=2+3t

dumbcow · Answer

by substitution:
t = (3-x)/2
then
y = 2+3(3-x)/2
which simplifies to 
y = (13-3x)/2

it is a linear line with slope of -3/2

anonymous · Answer

so how would my graph look like? and is that what they mean by eliminating the parameter?

dumbcow · Answer

yes what i did was eliminate the t parameter

dumbcow · Answer

the graph would be the line

anonymous · Answer

ok so now i have this question,

anonymous · Answer

when i do 
x=sqrt(t)
y=1-t 
be equal to
x^2 =t
y= 1-x^2

dumbcow · Answer

correct, though you may have to specify the domain as only positive values

anonymous · Answer

okk and my graph wouldbe|dw:1339643587000:dw|

dumbcow · Answer

yep

anonymous · Answer

ok thank you!! :D

dumbcow · Answer

your welcome