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An electric field of 259,000 N/C points due west at a certain spot. What are the magnitude and direction of the force that acts on a charge of -7.4 µC at this spot?
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V=q/c
Isn't this solved using E = F/q?
Also, since you're dealing with a negatively-charged particle, the electric field is in the direction opposite to the force. Hope that helps!
Continuing my response (sorry), I think I did the math right (paper and pencil); I got F = 1.9 N, pointing east.
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