An electric field of 259,000 N/C points due west at a certain spot. What are the magnitude and direction of the force that acts on a charge of -7.4 µC at this spot?

Question

goformit100 · Answer

V=q/c

anonymous · Answer

Isn't this solved using E = F/q?

anonymous · Answer

Also, since you're dealing with a negatively-charged particle, the electric field is in the direction opposite to the force. Hope that helps!

anonymous · Answer

Continuing my response (sorry), I think I did the math right (paper and pencil); I got F = 1.9 N, pointing east.