Question

find the area of segment with a 60 degree angle and 12 radius.

Answer 1

\[r ^{2}(\pi \Theta \div360-\sin \Theta \div2)\]

Answer 2

Area of Segment = ½ × ( (θ × π/180) - sin θ) × r2 (when θ is in degrees)

Answer 3

Why 1/2 @maheshmeghwal9

Answer 4

u see http://www.mathsisfun.com/geometry/circle-sector-segment.html

Answer 5

24pi-36sqrt3?

Answer 6

but it is the area of sector I think @ParthKohli

Answer 7

we have to find segment

Answer 8

's area